P + 5C2H5OH + 5/2 I2 ---> 5C2H5I + H3PO4 + H2O

m(P)=4.14g
m(C2H5OH)= 27.5g
m(I2)=63.5g
m(C2H5I)= 73g

Whats the percent yield of the reaction?
(Can someone more precisely explain how to solve the problem please)

How do you mean "more precisely"? Has it been explained before. What did you not understand.

DrBob222 more precisely how to find the limiting reagent on this one, and what to do next please

To calculate the percent yield of a reaction, you need to compare the actual yield of the desired product to the theoretical yield of the product. Theoretical yield is the maximum amount of product that could be obtained if the reaction went to completion based on the stoichiometry of the reaction.

In this case, you are given the masses of the reactants and the mass of the product. To determine the theoretical yield, you need to calculate the number of moles of each substance involved in the reaction.

First, let's calculate the number of moles for each substance:

molar mass of P (phosphorus) = 30.97 g/mol
number of moles of P = mass/molar mass = 4.14 g / 30.97 g/mol

molar mass of C2H5OH (ethanol) = 46.07 g/mol
number of moles of C2H5OH = mass/molar mass = 27.5 g / 46.07 g/mol

molar mass of I2 = 253.80 g/mol
number of moles of I2 = mass/molar mass = 63.5 g / 253.80 g/mol

molar mass of C2H5I (ethyl iodide) = 155.99 g/mol
number of moles of C2H5I = mass/molar mass = 73 g / 155.99 g/mol

Next, we need to determine the limiting reactant. The limiting reactant is the one that is completely consumed in the reaction and thus determines the maximum amount of product that can be produced. It is usually the reactant with the smallest number of moles.

To find the limiting reactant, we need to find the ratio of moles of each reactant to the coefficient in the balanced equation. The balanced equation is:

P + 5C2H5OH + 5/2 I2 ---> 5C2H5I + H3PO4 + H2O

The ratio of moles of P to moles of C2H5OH is 1:5.
The ratio of moles of P to moles of I2 is 1:5/2 (or 1:2.5).
The ratio of moles of P to moles of C2H5I is 1:5.

Comparing the ratios, it is clear that the limiting reactant is P since it has the smallest ratio.

Now, we can calculate the theoretical yield of C2H5I based on the moles of P:

moles of P * (moles of C2H5I/moles of P) * molar mass of C2H5I

Next, we need to convert the theoretical yield of C2H5I into grams.

Finally, we can calculate the percent yield by dividing the actual yield of C2H5I by the theoretical yield and multiplying by 100.

I hope this step-by-step explanation helps you to calculate the percent yield of the reaction accurately.

To find the percent yield of the reaction, you need to compare the actual yield of the product (C2H5I) to the theoretical yield of the product. The theoretical yield is the amount of product that would be obtained if the reaction went to completion, based on the balanced chemical equation.

First, you need to determine the limiting reactant, which is the reactant that is completely consumed in the reaction and determines the amount of product that can be formed. To do this, you can calculate the number of moles of each reactant:

1. Calculate the number of moles of P:
- The molar mass of P is 30.97 g/mol.
- Moles of P = mass of P / molar mass of P
= 4.14 g / 30.97 g/mol

2. Calculate the number of moles of C2H5OH:
- The molar mass of C2H5OH is 46.07 g/mol.
- Moles of C2H5OH = mass of C2H5OH / molar mass of C2H5OH
= 27.5 g / 46.07 g/mol

3. Calculate the number of moles of I2:
- The molar mass of I2 is 253.81 g/mol.
- Moles of I2 = mass of I2 / molar mass of I2
= 63.5 g / 253.81 g/mol

Now, using the balanced chemical equation, determine the stoichiometric ratio of the reactants to the product. From the balanced equation, you can see that the ratio of P to C2H5OH to C2H5I is 1:5:5.

4. Identify the limiting reactant:
- Compare the moles of each reactant to their stoichiometric ratio.
- The limiting reactant will be the one with the smallest ratio.
- In this case, the smallest ratio is for P, so P is the limiting reactant.

Next, calculate the theoretical yield of C2H5I based on the limiting reactant:

5. Calculate the moles of C2H5I produced:
- The stoichiometric ratio of P to C2H5I is 1:5.
- Moles of C2H5I = Moles of P × (5 moles of C2H5I / 1 mole of P)

6. Calculate the mass of C2H5I produced:
- The molar mass of C2H5I is 156.04 g/mol.
- Mass of C2H5I = Moles of C2H5I × Molar mass of C2H5I

Now, you can calculate the percent yield:

7. Calculate the percent yield:
- Percent yield = (Actual yield / Theoretical yield) × 100
- Actual yield is given as 73 g (mass of C2H5I).
- Theoretical yield was calculated in step 6 above (mass of C2H5I).
- Percent yield = (73 g / Theoretical yield) × 100

By following these steps, you should be able to calculate the percent yield of the reaction.