A positive test charge of 8.33 × 10−5 C is

placed in an electric field of 53.54 N/C intensity.
What is the strength of the force exerted on
the test charge?
Answer in units of N

c

To find the strength of the force exerted on the test charge, we can use the formula:

Force = Charge * Electric Field

Given:
Test charge = 8.33 × 10−5 C
Electric field intensity = 53.54 N/C

Step 1: Substitute the values into the formula:
Force = (8.33 × 10−5 C) * (53.54 N/C)

Step 2: Multiply the values:
Force = 4.442082 × 10−3 N

Step 3: Round the answer to the appropriate number of significant figures:
Force = 0.0044 N (rounded to 2 decimal places)

Therefore, the strength of the force exerted on the test charge is approximately 0.0044 N.

To find the strength of the force exerted on the test charge, you can use the formula:

F = q * E

where:
F represents the force,
q represents the charge of the test charge, and
E represents the electric field intensity.

Given:
q = 8.33 × 10^(-5) C (charge of the test charge),
E = 53.54 N/C (electric field intensity).

Now you can substitute the given values into the formula:

F = (8.33 × 10^(-5) C) * (53.54 N/C)

Solving this expression, we get:

F ≈ 0.00445 N

Therefore, the strength of the force exerted on the test charge is approximately 0.00445 N.