If you mix 10 mL of 6 M HCl (aq) and 10 mL of 3M NaOH, will the solution be acidic, neutral, or base?

you need to calculate the pH,to determine the solution

See above.

To determine the nature of the resulting solution, you need to consider the reaction between HCl (aq) and NaOH (aq), which is a neutralization reaction. In this reaction, the H+ ions from HCl react with the OH- ions from NaOH to form water (H2O). The HCl is a strong acid, and NaOH is a strong base.

The balanced chemical equation for the reaction is:

HCl (aq) + NaOH (aq) → H2O (l) + NaCl (aq)

Given that the initial concentration of HCl is 6 M and the initial concentration of NaOH is 3 M, you can determine the limiting reactant.

To find the limiting reactant, you need to calculate the number of moles of each reactant:

Moles of HCl = concentration (M) x volume (L) = 6 M x 0.010 L = 0.060 moles
Moles of NaOH = concentration (M) x volume (L) = 3 M x 0.010 L = 0.030 moles

Since the stoichiometric ratio between HCl and NaOH is 1:1, it is evident that NaOH is the limiting reactant since there are fewer moles of NaOH compared to HCl.

Now, let's consider the reaction between HCl and NaOH. Since NaOH is the limiting reactant, it will react completely with the available HCl:

0.030 moles of NaOH will react with 0.030 moles of HCl.

The excess HCl remaining after the reaction will be:

0.060 moles of HCl - 0.030 moles of HCl = 0.030 moles of HCl

The resulting solution will contain 0.030 moles of NaCl and no excess NaOH or HCl.

Since NaCl is a neutral salt, it will not contribute to the acidity or basicity of the solution. Therefore, the resulting solution will be neutral.