Posted by **pradyumna** on Friday, February 8, 2013 at 6:38am.

in a rectangular field adjacent sides differ by 17 cm.its diagonal length is 25 cm.find the cost of fencing the field at rs 5 per metre

- math -
**Steve**, Friday, February 8, 2013 at 10:36am
s^2 + (s+17)^2 = 25^2

s = 8

The field is 8x17 cm

What a tiny field!

cost is thus 2(8+17)cm * rs5/m * 1m/100cm = rs 2.5

How odd: since a=8,b=17

a+b = √(a^2+b^2)

- math - oops -
**Steve**, Friday, February 8, 2013 at 10:39am
My bad. I was thinking of an 8-15-17 triangle.

s=7

2(7+25)*5/100 = rs 3.20

- math -
**Steve**, Friday, February 8, 2013 at 10:39am
rats! still bad arithmetic

7+17=24, not 25

you fix it

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