Posted by pradyumna on Friday, February 8, 2013 at 6:38am.
in a rectangular field adjacent sides differ by 17 cm.its diagonal length is 25 cm.find the cost of fencing the field at rs 5 per metre

math  Steve, Friday, February 8, 2013 at 10:36am
s^2 + (s+17)^2 = 25^2
s = 8
The field is 8x17 cm
What a tiny field!
cost is thus 2(8+17)cm * rs5/m * 1m/100cm = rs 2.5
How odd: since a=8,b=17
a+b = √(a^2+b^2)

math  oops  Steve, Friday, February 8, 2013 at 10:39am
My bad. I was thinking of an 81517 triangle.
s=7
2(7+25)*5/100 = rs 3.20

math  Steve, Friday, February 8, 2013 at 10:39am
rats! still bad arithmetic
7+17=24, not 25
you fix it
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