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March 29, 2017

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A uniform rod of mass 100g has a length of 1m.it is supported horizantally on two knife edges placed 10cm from it end. What will be the reaction at these supports when a 50g mass is suspended 30cm from one of the knife edges?

  • Physics - ,

    from one knife edge
    center of rod is .4 meters
    added mass is .3 meters
    other knife edge is .8 m away from first

    total mass = .1 + .05 = .15 kg

    moment around close knife edge = g(.3*.05+.4*.1) = .055 g
    so
    F(.8) = .055 g
    F = .06875 g
    if g = 9.81 m/s^2
    F = .674 Newtons

    total weight = .15(9.81) = 1.47 N
    so other F = 1.47 - .674 = .798 Newtons

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