Posted by Usman on Friday, February 8, 2013 at 6:34am.
from one knife edge
center of rod is .4 meters
added mass is .3 meters
other knife edge is .8 m away from first
total mass = .1 + .05 = .15 kg
moment around close knife edge = g(.3*.05+.4*.1) = .055 g
so
F(.8) = .055 g
F = .06875 g
if g = 9.81 m/s^2
F = .674 Newtons
total weight = .15(9.81) = 1.47 N
so other F = 1.47 - .674 = .798 Newtons
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