# Differential Equations

posted by
**Erica** on
.

Locate the bifurcation values of a for the one-parameter family and describe the bifurcation that takes place at each such value.

dy/dt=e^(-y^2)+a

I got that the equilibrium points will be at -sqrt(ln(a)). I don't know if that is fine. I took the partial derivative with respect to y and got -2ye^(-y^2) and that is zero when a is 0 if I plug in -sqrt(ln(a)) as y.