Post a New Question

Differential Equations

posted by on .

Locate the bifurcation values of a for the one-parameter family and describe the bifurcation that takes place at each such value.
dy/dt=e^(-y^2)+a
I got that the equilibrium points will be at -sqrt(ln(a)). I don't know if that is fine. I took the partial derivative with respect to y and got -2ye^(-y^2) and that is zero when a is 0 if I plug in -sqrt(ln(a)) as y.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question