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Applied Calculus......

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Find the slope m of the tangent line to the graph of the function at the given point and determine an equation of the tangent line.

f(x)=6x-5x^2 at (-2, -32)

I have to use the four step process, but seem to be getting stuck...

  • Applied Calculus...... -

    slope=6-10x at x=-2
    slope=6+20=26
    that is pretty steep.

    y=mx+b
    -32=26*-2 + b
    solve for b, and you have the tangent line equation.
    y=26x+20 check the math , I did it in my head.

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