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April 24, 2014

April 24, 2014

Posted by **Jacob** on Thursday, February 7, 2013 at 8:25pm.

f(x)=6x-5x^2 at (-2, -32)

I have to use the four step process, but seem to be getting stuck...

- Applied Calculus...... -
**bobpursley**, Thursday, February 7, 2013 at 8:30pmslope=6-10x at x=-2

slope=6+20=26

that is pretty steep.

y=mx+b

-32=26*-2 + b

solve for b, and you have the tangent line equation.

y=26x+20 check the math , I did it in my head.

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