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January 30, 2015

January 30, 2015

Posted by **Anonymous** on Thursday, February 7, 2013 at 4:56pm.

I know that I have to solve using integration by parts and so I've let u=t to rid of dt and dv=e^-3t which I believe would yield -(1/3) * e^-3t as v. Am I doing this correctly?

Thanks. I appreciate the help. (:

- Calculus -
**Steve**, Thursday, February 7, 2013 at 5:01pmGood work. So,

∫ u dv = uv - ∫ v du

= -1/3 t e^-3t - ∫ (-1/3) e^-3t dt

and you're almost done

- Calculus -
**Anonymous**, Thursday, February 7, 2013 at 7:24pmAwesome, thanks for the help!

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