Saturday

December 20, 2014

December 20, 2014

Posted by **Anonymous** on Thursday, February 7, 2013 at 4:56pm.

I know that I have to solve using integration by parts and so I've let u=t to rid of dt and dv=e^-3t which I believe would yield -(1/3) * e^-3t as v. Am I doing this correctly?

Thanks. I appreciate the help. (:

- Calculus -
**Steve**, Thursday, February 7, 2013 at 5:01pmGood work. So,

∫ u dv = uv - ∫ v du

= -1/3 t e^-3t - ∫ (-1/3) e^-3t dt

and you're almost done

- Calculus -
**Anonymous**, Thursday, February 7, 2013 at 7:24pmAwesome, thanks for the help!

**Answer this Question**

**Related Questions**

Calculus II - Integrate using integration by parts (integral) (5-x) e^3x u = 5-x...

calc - evaluate the integral: y lny dy i know it's integration by parts but i ...

Calculus II - Evaluate the integral using method of integration by parts: (...

Calculus - Hello, I have some calculus homework that I can't seem to get started...

Calculus 2 - integral of xarctanxdx using integration by parts.

integration by parts - s- integral s ln (2x+1)dx ? = ln(2x+1)x - s x d( ln (2x+1...

Calculus - "Evaluate the following indefinite integral using integration by ...

Calculus - Hello, I'm having trouble with this exercise. Can you help me? ...

calculus - how do you solve the integral of 1/[(square root of x)(lnx)] from 2 ...

Math/Calculus - How would I evaluate the following integral by using integration...