Potassium superoxide (KO2)reacts in the following equation:

4KO2 + 2H2O +4CO2 =4KHCO3 + 3O2 If a person wearing an oxygen mask exhales 0.85 grams of CO2 every minute, how many moles of KO2 are comsumed every 10.0 minutes?

.85g CO2 = 0.019 moles

each mole of CO2 uses 1 mole KO2

so, .019 moles/min * 10 min = 0.19 moles KO2

To determine the number of moles of KO2 consumed every 10.0 minutes, we need to calculate the moles of CO2 exhaled in 10.0 minutes and then use the stoichiometric ratio from the balanced equation to find the moles of KO2 consumed.

First, let's calculate the moles of CO2 exhaled in 10.0 minutes:

1. Determine the moles of CO2 exhaled per minute:
Given: 0.85 grams of CO2 every minute
Atomic mass of carbon (C) = 12.01 g/mol
Atomic mass of oxygen (O) = 16.00 g/mol
Molar mass of CO2 = 12.01 g/mol + 2 * 16.00 g/mol = 44.01 g/mol

Moles of CO2 per minute = (0.85 g CO2) / (44.01 g/mol CO2) = 0.0193 mol CO2/minute

2. Calculate the moles of CO2 exhaled in 10.0 minutes:
Moles of CO2 in 10.0 minutes = (0.0193 mol CO2/minute) * 10.0 minutes = 0.193 mol CO2

Now, let's use the stoichiometric ratio from the balanced equation to find the moles of KO2 consumed:

From the equation: 4KO2 + 2H2O + 4CO2 = 4KHCO3 + 3O2
We see that 4 moles of KO2 react with 4 moles of CO2.

3. Calculate the moles of KO2 consumed in 10.0 minutes:
Moles of KO2 consumed = (0.193 mol CO2) * (4 mol KO2 / 4 mol CO2) = 0.193 mol KO2

Therefore, 0.193 moles of KO2 are consumed every 10.0 minutes when the person exhales 0.85 grams of CO2 every minute.

To find the number of moles of KO2 consumed every 10.0 minutes, we need to use the given information about the amount of CO2 exhaled.

First, we need to convert the mass of CO2 exhaled to moles.
The molar mass of CO2 is 44.01 g/mol.

Using the given mass of CO2:
0.85 grams of CO2 * (1 mol CO2 / 44.01 g CO2) = 0.0193 moles of CO2 per minute

Now, we can use the balanced equation to determine the stoichiometry between KO2 and CO2.
From the equation, we know that 4 moles of KO2 react with 4 moles of CO2.

Therefore, 0.0193 moles of CO2 corresponds to 0.0193 moles of KO2 per minute.

To calculate the moles of KO2 consumed every 10.0 minutes, we multiply this value by 10.0:
0.0193 moles KO2/minute * 10.0 minutes = 0.193 moles of KO2 consumed every 10.0 minutes.

Therefore, 0.193 moles of KO2 are consumed every 10.0 minutes.