Wednesday

June 29, 2016
Posted by **Anonymous** on Thursday, February 7, 2013 at 10:13am.

dy/dx = 2xy + (y^2/x^2)

- maths-urgently needed[Differential equations] -
**Steve**, Thursday, February 7, 2013 at 10:26amLooks like a Riccati equation. Standard methods, such as those at

http://www.sosmath.com/diffeq/first/riccati/riccati.html

will lead to the solution

y = xe^(x^2) / (cx + e^(x^2) - πix erf(ix))

where erf(x) is the error function. - maths-urgently needed[Differential equations] -
**Dr. Fairman**, Friday, February 15, 2013 at 1:54pmUse wolframalpha dot com - it will solve yr equation and show all steps.