Thursday

June 30, 2016
Posted by **Anonymous** on Thursday, February 7, 2013 at 6:16am.

dy/dx = 2xy + (y^2/x^2)

- maths-urgently needed[Differential equations] -
**Dr. Fairman**, Friday, February 15, 2013 at 1:57pmSolution:

{y[x] == (E^x^2 x)/(E^x^2 - Sqrt[Pi] x Erfi[x] + x Subscript[c, 1])}