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August 30, 2014

August 30, 2014

Posted by **Anonymous** on Wednesday, February 6, 2013 at 11:26pm.

I did it this way don't know if it's right

f(x)=1144.7(x-1990)+35,834

42,303-35,834 = 1144.7 - (x-1990) + 35,834

6469. 1144 7 - (x-1990). 35,834

.177=x-1990

The median income was $1144.7 every year

Thanks for all your help:-)

- college algebra -
**Steve**, Thursday, February 7, 2013 at 11:53amThe question was:

Determine when the median income was $42,303

Your answer does not fit the question. You started off right (I think). The posting is sort of garbled.

42303 = 1144.7(x-1990) + 35834

1144.7(x-1990) = 42303-35834

1144.7(x-1990) = 6469

x-1990 = 5.65

x = 1995.65

so, in late August 1995 the median income will be 42303.

You are sort of correct. The median income rises 1144.70 every year.

Since 42303 is 6469 more than the starting value of 35384, it takes 5.65 years to rise enough to reach the target value.

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