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college algebra

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Median family income in country x between 1990 and 1999 can be modeled by f(x)=1144.7(x-1990)+35,834 where x is the year. Determine the median income was $42,303.

I did it this way don't know if it's right
f(x)=1144.7(x-1990)+35,834
42,303-35,834 = 1144.7 - (x-1990) + 35,834
6469. 1144 7 - (x-1990). 35,834

.177=x-1990
The median income was $1144.7 every year

Thanks for all your help:-)

  • college algebra - ,

    F(x) = 1144.7(x-1990) + 35,834 = $42303.
    1144.7x for y - 2277953 + 35834 = 42303
    1144.7x - 2242119 = 42303
    1144.7x = 2284422
    X = 1995.65 or 1996.

    The Median income was $42,303 for year
    1996.

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