My family went to starbucks. We ordered 3 drinks. My daughter's drink was .90 cents less than my drink and my sons drink was $2.20 more than my drink. The total bill was $12.90. How much was each drink? Use algebra.
Please help me, thanx
lets call your drink cost x
your sons y
and daughters Z
so x+y+z=12.9
and y=x+2.2
and z=x-0.9
so x+x+2.2+x-0.9=12.9
solve for x
you get 3x=11.6
x=3.867
Sure, I can help you solve this problem using algebra. Let's assign variables to the unknowns:
Let's say the cost of your drink is x dollars.
Since your daughter's drink is $0.90 less than yours, her drink would cost (x - 0.90) dollars.
Similarly, your son's drink costs $2.20 more than yours, so his drink would cost (x + 2.20) dollars.
Now, let's set up an equation using the given information:
The total bill for the 3 drinks is $12.90, so we can write the equation as:
x + (x - 0.90) + (x + 2.20) = 12.90
Now, we can simplify and solve the equation:
3x + 1.30 = 12.90 (combine like terms)
3x = 12.90 - 1.30 (subtract 1.30 from both sides)
3x = 11.60 (simplify the right side)
x = 11.60 / 3 (divide both sides by 3)
x ≈ 3.87
So, the cost of your drink is approximately $3.87.
To find the cost of your daughter's drink, we substitute the value of x into the expression (x - 0.90):
Daughter's drink = 3.87 - 0.90 ≈ $2.97
And to find the cost of your son's drink, we substitute the value of x into the expression (x + 2.20):
Son's drink = 3.87 + 2.20 ≈ $6.07
Therefore, your drink cost approximately $3.87, your daughter's drink cost approximately $2.97, and your son's drink cost approximately $6.07.