Posted by Blake on .
2. Given the following data, calculate the Keq for the denaturation reaction of βlactoglobin at 25 oC.
Δ Ho = 88 kJ/mol, Δ So = 0.3 kJ/mol

biochemistry 
DrBob222,
dGo = dHo  TdSo
Solve for dG.
Then dG = RT*lnK
Solve for K.
Use 8.314 for R and 298.15 for T. 
biochemistry 
Devron,
Dr. Bob222 is completely correct about how to get the answer, but I think I know why you posted the question in the first place. You are correct to be kind of confused because ΔG does not equal ΔG'°, and they are not the same thing. However, since βlactoglobin is the reactant and product for its denaturing, ΔG= ΔG'°. Looking at the equation:
ΔG= ΔG'°+ RTlnQ
Q=products/reactants
since the products= the reactants, Q=1 and ln(1) is equal to 0, so ΔG= ΔG'°. With that being said, you can use ΔG=RT*lnK or K'eq=10^(ΔG'°/1.36) and solve for K'eq; both equations are the same.