Posted by **Blake** on Wednesday, February 6, 2013 at 9:08pm.

2. Given the following data, calculate the Keq for the denaturation reaction of β-lactoglobin at 25 oC.

Δ Ho = -88 kJ/mol, Δ So = 0.3 kJ/mol

- biochemistry -
**DrBob222**, Wednesday, February 6, 2013 at 10:07pm
dGo = dHo - TdSo

Solve for dG.

Then dG = -RT*lnK

Solve for K.

Use 8.314 for R and 298.15 for T.

- biochemistry -
**Devron**, Thursday, February 7, 2013 at 2:26am
Dr. Bob222 is completely correct about how to get the answer, but I think I know why you posted the question in the first place. You are correct to be kind of confused because ΔG does not equal ΔG'°, and they are not the same thing. However, since β-lactoglobin is the reactant and product for its denaturing, ΔG= ΔG'°. Looking at the equation:

ΔG= ΔG'°+ RTlnQ

Q=products/reactants

since the products= the reactants, Q=1 and ln(1) is equal to 0, so ΔG= ΔG'°. With that being said, you can use ΔG=-RT*lnK or K'eq=10^(-ΔG'°/1.36) and solve for K'eq; both equations are the same.

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