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college algebra

posted by on .

Passing through point (1,4); perpendicular to
2x+y=5
How do I solve this? I think it might be this but not sure please let me know what step I left out
Thanks:-)

2x+y=5
y=5-2x
y=2x-5
M1=2

4=-1/2(1)+c=1+c
C=4
Y=-1/4x-1

  • college algebra - ,

    from y = 5 - 2x
    y = -2x + 5 , (why did you switch the signs in yours ???)
    the slope is -2

    so the slope of the new line is 1/2

    y = (1/2)x + b
    sub in the point (4,1)
    4 = (1/2)(1) + b
    4 - 1/2 = b
    b = 7/2

    new equation is
    y = (1/2)x + 7/2

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