Posted by Anonymous on Wednesday, February 6, 2013 at 7:07pm.
Passing through point (1,4); perpendicular to
2x+y=5
How do I solve this? I think it might be this but not sure please let me know what step I left out
Thanks:)
2x+y=5
y=52x
y=2x5
M1=2
4=1/2(1)+c=1+c
C=4
Y=1/4x1

college algebra  Reiny, Wednesday, February 6, 2013 at 7:35pm
from y = 5  2x
y = 2x + 5 , (why did you switch the signs in yours ???)
the slope is 2
so the slope of the new line is 1/2
y = (1/2)x + b
sub in the point (4,1)
4 = (1/2)(1) + b
4  1/2 = b
b = 7/2
new equation is
y = (1/2)x + 7/2