Posted by **Anonymous** on Wednesday, February 6, 2013 at 7:07pm.

Passing thru point (1,4); perpendicular to

2x+y=5

How do I solve this? I think it might be this but not sure please let me know what step I left out

Thanks:-)

2x+y=5

y=5-2x

y=2x-5

M1=2

4=-1/2(1)+c=1+c

C=4

Y=-1/4x-1

- college algebra -
**Reiny**, Wednesday, February 6, 2013 at 7:35pm
from y = 5 - 2x

y = -2x + 5 , (why did you switch the signs in yours ???)

the slope is -2

so the slope of the new line is 1/2

y = (1/2)x + b

sub in the point (4,1)

4 = (1/2)(1) + b

4 - 1/2 = b

b = 7/2

new equation is

y = (1/2)x + 7/2

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