physics
posted by louis on .
An airplane with a speed of 80.9 m/s is climbing upward at an angle of 64.5 ° with respect to the horizontal. When the plane's altitude is 795 m, the pilot releases a package. (a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth. (b) Relative to the ground, determine the angle of the velocity vector of the package just before impact.

a. h = 0.5g*t^2 = 795 m.
4.9*t^2 = 795
t^2 = 162.24
Tf = 12.74 s. = Fall time.
d = 80.9*cos64.5 * 12.74 = 444 m.