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March 26, 2017

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A dolphin jumps with an initial velocity of 13.0at an angle of 44.0 above the horizontal. The dolphin passes through the center of a hoop before returning to the water. If the dolphin is moving horizontally when it goes through the hoop, how high above the water is the center of the hoop?

  • Physics - ,

    initial vertical velocity = Vi =13 sin 44
    = 9.03 m/s (I assume you mean meters/second )

    v = Vi - g t
    0 = 9.03 - 9.81 t
    t = .9205 second

    h = (1/2) g t^2
    = 4.9(.9205)^2
    = 4.15 meters

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