posted by Meredith on .
A dolphin jumps with an initial velocity of 13.0at an angle of 44.0 above the horizontal. The dolphin passes through the center of a hoop before returning to the water. If the dolphin is moving horizontally when it goes through the hoop, how high above the water is the center of the hoop?
initial vertical velocity = Vi =13 sin 44
= 9.03 m/s (I assume you mean meters/second )
v = Vi - g t
0 = 9.03 - 9.81 t
t = .9205 second
h = (1/2) g t^2
= 4.15 meters