Posted by **Jackie** on Wednesday, February 6, 2013 at 11:00am.

A ball is shot into the air from a bridge, and its height, y, in feet, above the ground t seconds after it is thrown is given by y=f(t) = −16t2 + 55t + 33.

What is the average velocity of the ball during the first second? Round your answer to two decimal places.

- Calculus help! -
**Steve**, Wednesday, February 6, 2013 at 12:17pm
the average velocity will be distance traveled divided by the time interval

y(0) = 33

y(1) = 72

avg v = 72-33 = 39

Or,

v = -32t + 55

avg is the ∫[0,1]v(t)/(1-0)

Note that the value is just that figured above.

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