Posted by **Jackie** on Wednesday, February 6, 2013 at 11:00am.

A ball is shot into the air from a bridge, and its height, y, in feet, above the ground t seconds after it is thrown is given by y=f(t) = −16t2 + 55t + 33.

What is the average velocity of the ball during the first second? Round your answer to two decimal places.

- Calculus help! -
**Steve**, Wednesday, February 6, 2013 at 12:17pm
the average velocity will be distance traveled divided by the time interval

y(0) = 33

y(1) = 72

avg v = 72-33 = 39

Or,

v = -32t + 55

avg is the ∫[0,1]v(t)/(1-0)

Note that the value is just that figured above.

## Answer This Question

## Related Questions

- Calculus - Suppose a ball is thrown straight up into the air, and the height of...
- math - A person standing on the roof of a building throws a ball directly upward...
- Pre-Calculus - A ball is thrown up at the edge of a 364 foot cliff. The ball is ...
- math - An object that is falling or vertically projected into the air has it ...
- Math/calculus - a toy rocket is shot into the air at the top of a building so ...
- Algebra - A ball is thrown into the air. The height in feet of the ball can be ...
- Calculus - If a ball is thrown straight up into the air with an initial velocity...
- Calculus - 1.if a ball is thrown into the air with a velocity of 35ft/s, it's ...
- math - If a ball is thrown straight up into the air with an initial velocity of ...
- algebra - a rock is thrown into the air from a height of 4 feet. the height of ...

More Related Questions