Posted by Jackie on Wednesday, February 6, 2013 at 11:00am.
A ball is shot into the air from a bridge, and its height, y, in feet, above the ground t seconds after it is thrown is given by y=f(t) = −16t2 + 55t + 33.
What is the average velocity of the ball during the first second? Round your answer to two decimal places.

Calculus help!  Steve, Wednesday, February 6, 2013 at 12:17pm
the average velocity will be distance traveled divided by the time interval
y(0) = 33
y(1) = 72
avg v = 7233 = 39
Or,
v = 32t + 55
avg is the ∫[0,1]v(t)/(10)
Note that the value is just that figured above.
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