Posted by maam on Wednesday, February 6, 2013 at 6:35am.
lim (xpi/2) (pi2x)^cosx

a  Reiny, Wednesday, February 6, 2013 at 11:23am
if x > π/2 , then cosπ/2 > 0
anything^0 = 1
so lim (π  2x)^cosx , as x>π/2
= 1

a  Steve, Wednesday, February 6, 2013 at 12:34pm
However, pi2x>0 as well, and 0^0 is undefined
Haven't figured out yet the proof. L'Hospital's Rule seems not to help much, taking logs.
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