Posted by **maam** on Wednesday, February 6, 2013 at 6:35am.

lim (x--pi/2) (pi-2x)^cosx

- a -
**Reiny**, Wednesday, February 6, 2013 at 11:23am
if x --> π/2 , then cosπ/2 ---> 0

anything^0 = 1

so lim (π - 2x)^cosx , as x--->π/2

= 1

- a -
**Steve**, Wednesday, February 6, 2013 at 12:34pm
However, pi-2x->0 as well, and 0^0 is undefined

Haven't figured out yet the proof. L'Hospital's Rule seems not to help much, taking logs.

## Answer this Question

## Related Questions

- Calculus..more help! - I have a question relating to limits that I solved lim(x...
- Calculus - Find the following limits algebraically or explain why they don’t ...
- maths - 1)lim [(x+y)sec(x+y)-xsecx]/ y x-o 2)show that lim |x-4|/x-4 does not ...
- CALCULUS - Could someone please solve these four problems with explanations? I'd...
- Calculus - How do I solve lim(x-->pi/4)(sinx-cosx)/cos(2x) The (x-->pi/4) ...
- Math - Evaluate the limits lim x^3 + 3/ x->¤ 2x^3 + 4x + 1 lim 1 - cosx / x-&...
- calculus - using L'Hospital's rule, evalutate; LIM as x->0 e^x +cos x / e^x...
- Pre-Calc - Trigonometric Identities Prove: (tanx + secx -1)/(tanx - secx + 1)= ...
- Math - Verify the identity . (cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant ...
- Trigonometry Check - Simplify #3: [cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [...

More Related Questions