Posted by Alexis on Wednesday, February 6, 2013 at 6:06am.
convert to moles and see which reagent gets used up:
32g CaCO3 = 32/100 = 0.32 moles
11g HCl = 11/36.46 = 0.30 moles
From the equation, each mole CaCO3 requires 2 moles HCl. So, only 0.15 moles of CaCO3 will be used, producing 0.15 moles CaCl2
.15 moles CaCl2 = .15*110.98 = 1.65g CaCl2
Oops 16.65g
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