When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.

CaCO3(s)+2HCl(aq)--> CaCl2(aq)+H2O (l)+CO2(g)
How many grams of calcium chloride will be produced when 32.0 g of calcium carbonate are combined with 11.0 g of hydrochloric acid?

convert to moles and see which reagent gets used up:

32g CaCO3 = 32/100 = 0.32 moles
11g HCl = 11/36.46 = 0.30 moles

From the equation, each mole CaCO3 requires 2 moles HCl. So, only 0.15 moles of CaCO3 will be used, producing 0.15 moles CaCl2

.15 moles CaCl2 = .15*110.98 = 1.65g CaCl2

Oops 16.65g

Where did you get .15 moles of CaCl2 from?

To find the number of grams of calcium chloride produced, we need to use the given balanced chemical equation and the concept of stoichiometry.

Step 1: Convert grams to moles
Given:
- Calcium carbonate (CaCO3) = 32.0 g
- Hydrochloric acid (HCl) = 11.0 g

To convert grams of a substance to moles, we need to use the molar mass of that substance. The molar mass of a compound is the sum of the atomic masses of all the elements present.

The molar masses are:
- Molar mass of CaCO3 = 40.08 g/mol (calcium) + 12.01 g/mol (carbon) + 3 * 16.00 g/mol (oxygen) = 100.09 g/mol
- Molar mass of HCl = 1.01 g/mol (hydrogen) + 35.45 g/mol (chlorine) = 36.46 g/mol

Now we can calculate the number of moles:
- Moles of CaCO3 = 32.0 g / 100.09 g/mol = 0.3196 mol
- Moles of HCl = 11.0 g / 36.46 g/mol = 0.3019 mol (rounded to four decimal places)

Step 2: Determine the stoichiometry
From the balanced chemical equation:
1 mole of CaCO3 reacts with 2 moles of HCl to produce 1 mole of CaCl2.

This means that the molar ratio between CaCO3 and CaCl2 is 1:1, and the molar ratio between HCl and CaCl2 is 2:1.

Step 3: Calculate the moles of CaCl2 produced
Since the molar ratio between HCl and CaCl2 is 2:1, we can say that the moles of CaCl2 produced are also 0.3019 mol (since the moles of HCl and CaCl2 are the same in this reaction).

Step 4: Convert moles to grams
The molar mass of CaCl2 is 40.08 g/mol (calcium) + 2 * 35.45 g/mol (chlorine) = 110.98 g/mol.

Now we can calculate the mass of CaCl2 produced:
- Mass of CaCl2 = 0.3019 mol * 110.98 g/mol = 33.5 g (rounded to one decimal place)

So, when 32.0 g of calcium carbonate are combined with 11.0 g of hydrochloric acid, approximately 33.5 grams of calcium chloride will be produced.