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April 25, 2014

April 25, 2014

Posted by **anonymous** on Wednesday, February 6, 2013 at 3:25am.

- physics -
**EDSEL**, Saturday, February 9, 2013 at 11:32pmANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH

K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM

0+0.5MVSQUARE=M(9.81)(0.1)

V=1.400 MASS M/SEC

90% LOSE OF ENERGY

M.E=MASS(G)(H) @ THE TOP

M.E=MASS (9.81)(0.1)

M.E=MASS 0.981

REDUCTION OF 90% DURING BOUNCE

M.E= MASS 0.981-MASS 0.981(0.9)

M.E= MASS 0.0981

MASS 0.0981=MASS (9.81)(H)

H=0.01M OR 1CM

edsel salariosa

- physics -
**EDSEL**, Saturday, February 9, 2013 at 11:36pmANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH

K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM

0+0.5MassVSQUARE=Mass(9.81)(0.1)+0

V=1.400 MASS M/SEC

90% LOSE OF ENERGY

M.E=MASS(G)(H) @ THE TOP

M.E=MASS (9.81)(0.1)

M.E=MASS 0.981

REDUCTION OF 90% DURING BOUNCE

M.E= MASS 0.981-MASS 0.981(0.9)

M.E= MASS 0.0981

MASS 0.0981=MASS (9.81)(H)

H=0.01M OR 1CM

since the mass of a object doesn't given you can cancel both side of the equation and you can find the height

edsel salariosa

research and development engineer

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