Posted by anonymous on .
A rotten cranberry will lose at least 90% of its total energy during a bounce. If the cranberries are dropped from a height of 10 cm, what is the minimum height in cm of the wall so that no rotten cranberries could ever bounce over it?

physics 
EDSEL,
ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH
K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM
0+0.5MVSQUARE=M(9.81)(0.1)
V=1.400 MASS M/SEC
90% LOSE OF ENERGY
M.E=MASS(G)(H) @ THE TOP
M.E=MASS (9.81)(0.1)
M.E=MASS 0.981
REDUCTION OF 90% DURING BOUNCE
M.E= MASS 0.981MASS 0.981(0.9)
M.E= MASS 0.0981
MASS 0.0981=MASS (9.81)(H)
H=0.01M OR 1CM
edsel salariosa 
physics 
EDSEL,
ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH
K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM
0+0.5MassVSQUARE=Mass(9.81)(0.1)+0
V=1.400 MASS M/SEC
90% LOSE OF ENERGY
M.E=MASS(G)(H) @ THE TOP
M.E=MASS (9.81)(0.1)
M.E=MASS 0.981
REDUCTION OF 90% DURING BOUNCE
M.E= MASS 0.981MASS 0.981(0.9)
M.E= MASS 0.0981
MASS 0.0981=MASS (9.81)(H)
H=0.01M OR 1CM
since the mass of a object doesn't given you can cancel both side of the equation and you can find the height
edsel salariosa
research and development engineer