physics
posted by aritro on .
A coin of mass 3 g slides horizontally on the surface of a table. The frictional force exerted on the penny is 0.0147 N. What is the coefficient of friction between the table and the penny?

0.0147=Fn(µk)= (0.003kg)(9.8m/s^2)µk
solve for µk
0.0147/[(0.003kg)(9.8m/s^2)]=µk