Posted by suie on Tuesday, February 5, 2013 at 8:48pm.
e^x (x^3 - 4) = 0
e^x = 0
x = -oo
x^3 = 4
x = 4^(.333....)
Not sure if you do complex arithmetic
360/3 = 120
if so you also have two complex roots
one at +120 degrees and one at - 120
x = r (cos 120 + i sin 120)
x = 4^(1/3) ( -.5 + i sqrt3/2)
x = 4^.3333...(.5)(-1+isqrt 3)
and the other is
x = 4^.3333...(.5)(-1-isqrt 3)
but the answers are 0,-2,2
If the equation is as you typed my money is riding with Damon.
Your answers don't even come close to satisfying the equation.
are u sure b/c the answers are from the book
Related Questions
Calculus II - Integrate using integration by parts (integral) (5-x) e^3x u = 5-x...
Pre-Calculus - Write the standard form of the equation of the circle that passes...
maths - hi, i would really appreciate some help on simplifying this question: -2...
Calculus - Evaluate (integral) e^3x dx. A. e^3x + C B. 1/3e^3x + C C. e^4x + C D...
Math - Can you help me with this? I did this many times and got different ...
Physics - Which of the following equations describes the condition for observing...
Calculus - Use implicit differentiation to find dy/dx. e^4x = sin(x+2y). This is...
Calculus - Find the equation of the line tangent to the graph of y=4 e^x at x=2...
pre-calculus - 2y^-3 = 4e^(-x/2)/(1+e(-x/2)) my teacher gave this problem in my ...
Math - "Solving a system involving three unknowns." 3d+e-2f=-14 2d-3e...
For Further Reading