Near San Francisco, where the vertically downward component of the earth's magnetic field is 6.8 x 10-5 T, a car is traveling forward at 17 m/s. The width of the car is 2.1 m. Find the emf induced between the two sides of the car. If positive charge accumulates on the driver's side, the enter the emf as a positive number. If negative charge accumulates on the driver's side, the enter the emf as a negative number.
To find the induced electromotive force (emf) between the two sides of the car, we can use the equation:
emf = B * v * d,
where B represents the magnetic field strength, v is the velocity of the car, and d is the width of the car.
Given:
Vertical component of magnetic field, B = 6.8 × 10^(-5) T,
Velocity of the car, v = 17 m/s,
Width of the car, d = 2.1 m.
Substituting these values into the equation, we get:
emf = (6.8 × 10^(-5) T) * (17 m/s) * (2.1 m).
Now, let's calculate this:
emf = (6.8 × 10^(-5) * 17 * 2.1) T * m/s * m.
emf = 0.0026784 T * m^2/s.
Therefore, the emf induced between the two sides of the car is 0.0026784 T * m^2/s.
Since it is not specified whether positive or negative charge accumulates on the driver's side, we can simply enter the emf as a positive value: 0.0026784 T * m^2/s.