Posted by **Julia** on Tuesday, February 5, 2013 at 7:56pm.

A stone is aimed at a cliff of height h with an initial speed of v = 64.0 m/s directed 55.0° above the horizontal, as shown in the Figure below by the arrow. The stone strikes at A, 7.31 s after launching. What is the height of the cliff?

What is the maximum height H reached above the ground?

I have tried using this formula but something isn't right?

D=ViT + 1/2aT^2

D=(64)(7.31)+ (4.9)(7.31)^2

D=729.68m

- Physics please help!! -
**0i99**, Monday, February 2, 2015 at 4:10am
hyu

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