Physics please help!!
posted by Julia on .
A stone is aimed at a cliff of height h with an initial speed of v = 64.0 m/s directed 55.0° above the horizontal, as shown in the Figure below by the arrow. The stone strikes at A, 7.31 s after launching. What is the height of the cliff?
What is the maximum height H reached above the ground?
I have tried using this formula but something isn't right?
D=ViT + 1/2aT^2
D=(64)(7.31)+ (4.9)(7.31)^2
D=729.68m

hyu