Posted by Ted on Tuesday, February 5, 2013 at 4:11pm.
I will let A be (-4,2) and B(-1,3)
vector AB = ( -1+4 , 3-2)
= (3,1)
magnitude of AB = √(3^2 + 1^2) = √10
let D be (x,y)
the vector CD = (x+6, x-0) = (x+6 , y)
but if vector AB = vector CD
then x+6 = 3
x = -3
and y = 1
so point D is (-3,1)
in general if A is the point (a,b) and B is the point (c,d)
then vector AB = ( c-a , d-b)
and vector BA = ( a - c, b - d)
note that vector AB = - vector BA
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