posted by Rachel on .
A ball is shot from the ground into the air. At a height of 9.1 m, the velocity is observed to be v = (6.6 + 5.7 ) m/s, with horizontal and upward.
(a) To what maximum height does the ball rise?
(b) What total horizontal distance does the ball travel?
(c) What is the magnitude of the ball's velocity just before it hits the gound?
(d)What is the direction of the ball's velocity just before it hits the ground?
° relative to the horizontal
6.7²/(2g) + 9.1 = 11.39 m
b) t = 2√[2H/g] = 3.05 sec; X = 6.6*t = 20.125 m
c) Vf = (6.6i - 6.7j) m/s
d) Θ = arctan[j/i] = arctan[-6.7/6.6] = -45.43°