Math Algebra 2
posted by AM .
#4. Express the logarithm in terms of log2M and log2N:
log2 1/MN
#5. Simplify:
log4 3  log4 48
#6. Solve the equation:
loga x = 3/2loga 9 + loga 2
#7. Solve the equation:
logb (x2 + 7) = 2/3logb 64
#8. Solve the equation:
loga (3x + 5)  loga (x  5) = loga 8

log2(1/MN) = log2(MN) = (log2M + log2N)
log4(3)log4(48) = log4(3/48) = log4(1/16) = log4(4^2) = 2
loga(x) = 3/2 loga(9) + loga(2)
loga(x) = loga(27*2)
x = 54
logb(x^2+7) = logb(16)
x^2+7 = 16
x^2 = 9
x = ±3
loga(3x+5)loga(x5) = loga(8)
loga((3x+5)/(x5)) = loga(8)
(3x+5)/(x5) = 8
x = 9