Monday

March 2, 2015

March 2, 2015

Posted by **Krissy** on Tuesday, February 5, 2013 at 11:18am.

1. Use the discriminant to determine whether the given equation has two irrational roots, two rational roots, one repeated root, or two complex roots.

x^2-4x=5

a.) Two rational roots

b.) one repreated root

c.) two complex roots

d.) two irrational roots.

2.Use the discriminant to determine whether the given equation has two irrational roots, two rational roots, one repeated root, or two complex roots.

-3x^3+19x-20=0

a.) Two rational roots

b.) one repreated root

c.) two complex roots

d.) two irrational roots.

3. Use the discriminant to determine whether the given equation has two irrational roots, two rational roots, one repeated root, or two complex roots.

-5x^2-7x-5=0

a.) Two rational roots

b.) one repreated root

c.) two complex roots

d.) two irrational roots.

4. Use the discriminant to determine whether the given equation has two irrational roots, two rational roots, one repeated root, or two complex roots

x^2-12=7x

a.) Two rational roots

b.) one repreated root

c.) two complex roots

d.) two irrational roots.

- College Algebra--Still Confused -
**Bosnian**, Tuesday, February 5, 2013 at 11:23amIn google type:

quadratic equation online

When you see list of result click on:

Free Online Quadratic Equation Solver:Solve by Quadratic Formula

When page be open in rectangle type your equation

and cilck option:

solve it!

You will see solutions step-by step and discriminant discusion.

- College Algebra--Still Confused -
**Damon**, Tuesday, February 5, 2013 at 11:27amI am only going to do one,

1. Use the discriminant to determine whether the given equation has two irrational roots, two rational roots, one repeated root, or two complex roots.

x^2-4x=5

a.) Two rational roots

b.) one repreated root

c.) two complex roots

d.) two irrational roots.

----------------

Write with a zero on the right in form

a x^2 + b x + c = 0

1 x^2 -4 x - 5 = 0

b^2 = (-4)(-4) = 16

-4ac = -4(1)(-5) = +20

so

b^2 -4ac = 16+20 = 36

sqrt (b^2 - 4ac) = +6

THAT means:

x = [ 4 +/- 6 ] /2

Two REAL Rational roots

BECAUSE

sqrt (+36) is a real number

sqrt (+36) is not sqrt( 0) which would give one repeated root

sqrt(+36) is not sqrt(-36) which would leave you with a +/- 6i which is COMPLEX number

it is not sqrt (2) or something which is not a nice rational number and can not be expressed as a ratio of whole numebers

**Answer this Question**

**Related Questions**

College Algebra - I have a few more questions that I'm not understanding. Its ...

College Algebra - I need some help with a few problems. They are multiple choice...

Math problem still stuck - Let f(x) = 1/(x+7)+15/(x-8). Find all a for which f(a...

Calc- Derivatives - So, I have a bunch of derivative problems for homework and ...

Excel - I have to create a payroll document for class using Excel and I am quite...

english - grammar - hello! I have some problems with mixed conditional.I ...

Business Communication - Which way of asking for action carries the highest ...

College Algebra - I have a few problems I need help with and also do have ...

English for john browm - Let me give you something on "multiple-choice" items ...

Math check 3 - f(x) = 1/(x+7)+15/(x-8). Find all a for which f(a)=f(a+15). I ...