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July 23, 2014

July 23, 2014

Posted by **AM** on Tuesday, February 5, 2013 at 10:57am.

#1.Express the logarithm in terms of log2M and log2N:

log2(MN)4

#2. Express the logarithm in terms of log2M and log2N:

log2 the cube root of M2N

#3. Express the logarithm in terms of log2M and log2N:

log2 (M/N)7

#4. Express the logarithm in terms of log2M and log2N:

log2 1/MN

#5. Simplify:

log4 3 - log4 48

#6. Solve the equation:

loga x = 3/2loga 9 + loga 2

#7. Solve the equation:

logb (x2 + 7) = 2/3logb 64

#8. Solve the equation:

loga (3x + 5) - loga (x - 5) = loga 8

- Math Algebra 2 -
**Damon**, Tuesday, February 5, 2013 at 11:14amIn my Ti83 you have your choice of log key which is log base ten and ln key which is log base e

1.

log (4 M N) = log 4 + log M + log N

or perhaps you mean

log (MN)^4

which is

4 (log M + log N)

2.

do you mean M^2 N ????

(1/3)(2 log M + log N)

3.

(1/7) (log M - log N)

These are all the same. I am bored.

- Math Algebra 2 -
**Damon**, Tuesday, February 5, 2013 at 11:15amIn my Ti83 you have your choice of log key which is log base ten and ln key which is log base e

1.

log (4 M N) = log 4 + log M + log N

or perhaps you mean

log (MN)^4

which is

4 (log M + log N)

2.

do you mean M^2 N ????

(1/3)(2 log M + log N)

3.

(1/7) (log M - log N)

These are all the same. I am bored.

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