Posted by **Anonymous** on Tuesday, February 5, 2013 at 2:06am.

A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the drawn ball is red.

- maths -
**Reiny**, Tuesday, February 5, 2013 at 8:49am
consider the result as 2 independent events

bag1, red

bag2, red

Prob(bag1,red) = (1/2)(4,7) = 2/7

prob(bag2,red) = (1/2)2/6) = 1/6

prob(your event) = 2/7 + 1/6 = 19/42

## Answer This Question

## Related Questions

- Maths - Bag A contains 2 white, 1 black and 3 red balls, Bag B contains 3 white...
- MATH 12 HELP! - One bag contains 4 white balls and 6 black balls. Another bag ...
- maths-probabilty - Bag 1 contains 2 white and 3 red balls and bag 2 contains 4 ...
- maths- probabilty(me posted third time)plse answer - There are two bags out of ...
- maths-probabilty(URGENTLYYY) - There are two bags out of which Bag 1 contains 2 ...
- FINITE - selection of colored balls from two bags. Assume that each bag contains...
- maths-probabilty - There are two bags out of which Bag 1 contains 2 white and 3 ...
- ******MATH 12******* - How about this. One bad contains 4 white balls and 6 ...
- Statistics HELP - There are two bags each containing red balls and yellow balls...
- Math - A bag contains 5 red balls and 4 white balls. Two balls are drawn at ...

More Related Questions