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August 28, 2014

August 28, 2014

Posted by **AwesomeGuy** on Monday, February 4, 2013 at 10:13pm.

- Trigonometry -
**Reiny**, Monday, February 4, 2013 at 11:01pmMy diagram has the lighthouse as PQ with P at the top and PQ = 350

My ships are at A and B, angle at A = 4° and the angle at B = 6.5°

In the right angled triangle BQP

sin 6.5 = 350/BP

BP = 350/sin 6.5 = .....

now look at triangle ABP

we just found BP

and angle ABP = 173.5°

thus angle APB = 180 - 4 - 173.5 = 2.5°

by the sine law:

AB/sin 2.5 = BP/sin 4°

I will let you finish this, let me know what you got.

- Trigonometry -
**AwesomeGuy**, Tuesday, February 5, 2013 at 1:56amBP= 3091.79

AB/sin 2.5° = 3091.79/sin 4°

3091.785015 sin 2.5° = 134.8617682

134.8617682/sin 4° = 1933.33

Awesome! Thanks for the help!

- Trigonometry -
**AwesomeGuy**, Tuesday, February 5, 2013 at 2:04amSince I have also forgot to label the conversion for the solution, it is ultimately measured in FEET.

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