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February 1, 2015

February 1, 2015

Posted by **AwesomeGuy** on Monday, February 4, 2013 at 9:58pm.

A surveyor wishes to find the distance across a swamp. The bearing from A to B (Segment AB is opposite side of triangle) is N 32° W. The surveyor walks 50 meters from A to C, and at the point C the bearing to B is N 68° W. (Segment AC is adjacent side of triangle & Segment BC is hypotenuse side of triangle.)

A) Find bearing from A to C?

B) What is the distance from A to B?

- Trigonometry -
**Reiny**, Monday, February 4, 2013 at 10:41pmConfusing description. Where does the swamp come in ?

After a few tries I got a right-angled triangle with angle A = 90°

I sketched a vertical line AP .

From your description, angle BAP = 32°, leaving

angle PAC = 58°

I also drew a vertical from C to Q

so that angle QCB = 68°

let angle BCA = Ø

since AP and CQ are parallel

angle PAC + angle ACQ = 180°

58 + Ø+68=180

Ø = 54°

OK then....

A) bearing from A to C is N 58° E

B) tan 54° = AB/50

AB = 50tan54 = 68.82 m

- Trigonometry -
**AwesomeGuy**, Tuesday, February 5, 2013 at 2:22amReiny thanks a lot for the help! I welcome you with a nice smile! Here is the website where I can show how the problems look/appear like...

Google this:

4.8 applications and models Comcast

Click the first result that appears on the web search page.

Go to page 8 in the PDF document on problem #33.

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