Posted by Kristen on Monday, February 4, 2013 at 9:21pm.
All these are based on the following concept (should be in your text)
for ax^2 + bx + c = 0
if b^2 - 4ac < 0 there are two imaginary or complex roots
if b^2 - 4ac = 0 , there is one root, (one repeated root)
if b^2 - 4ac > 0 , there are two distinct and real roots
if for the last case, b^2 - 4ac is a perfect square, then the two real roots will be rational, otherwise they are irrational.
in each case, evaluate b^2 - 4ac and decide where it fits in
remember to arrange the equation in the proper form
I will do #4
x^2 - 12 = 7x
x^2 - 7x - 12 = 0 , a=1, b=-7 , c= -12
b^2 - 4ac
= 49 - 4(1)(-12) = +97
so we will have 2 irrational roots
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