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July 31, 2014

July 31, 2014

Posted by **Liz** on Monday, February 4, 2013 at 3:43pm.

- Calculus -
**Steve**, Monday, February 4, 2013 at 3:52pmThe curves intersect at (0,0) and (2,2)

v = ∫[0,2] π(R^2-r^2) dy

where R = √y and r = y/2

v = ∫[0,2] π(y-y^2/4) dy

= π(y^2/2 - y^3/12) [0,2]

= 4π/3

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