net ionic equation for KI+Na2So2O3+KCl
I wonder what the reaction is.
as do I.
Student
To write the net ionic equation for the given reaction, we first need to know the chemical formulas of the compounds involved.
The chemical formulas are:
- KI (Potassium Iodide)
- Na2S2O3 (Sodium Thiosulfate)
- KCl (Potassium Chloride)
Next, we need to balance the equation by determining the products formed. The reaction can be written in its balanced form as follows:
2 KI + Na2S2O3 + 2 KCl → 2 KCl + NaI + S2O3
Now, let's break down the equation into ions to identify the spectator ions and write the net ionic equation:
2 K+ + 2 I- + 2 Na+ + S2O3 → 2 K+ + 2 Cl- + Na+ + I- + S2O3
From the net ionic equation, it's clear that the spectator ions are Na+ and S2O3. Therefore, they can be removed from the equation:
2 K+ + 2 I- + 2 Cl- → 2 K+ + 2 Cl- + I-
Simplifying the equation further, we get:
2 I- → I-
Therefore, the net ionic equation for the given reaction is:
2 I- → I-