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March 3, 2015

March 3, 2015

Posted by **Anonymous** on Monday, February 4, 2013 at 6:03am.

at the end of the second year; how much should he pay at the end of the 3rd year in order to clear the account?

- maths -
**Reiny**, Monday, February 4, 2013 at 8:47amx + 8000(1.05) + 6000(1.05)^2 = 1800(1.05)^3

...

....

x =5822.25

( For these I make a "time graph"

on a line, mark 0 (now), year 1, year 2 , and year 3

Place 18000 above the "now"

place 6000 at 1, 8000 at 2, and x at 3

"move" all monies to position 3 )

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