Posted by Ellie on Monday, February 4, 2013 at 5:22am.
The acceleration of gravity (g) is 9.81 m/s^2 on Earth and 1.63 m/s^2 on the moon. It is therefore higher on Earth by a factor of 6.02.
The period of a pendulum is
P = 2 pi sqrt(L/g)
Since you are using the same clock in both places, L stays the same and the period will be longer by a factor sqrt6.01 = 2.45 on the moon.
On Earth, a clock's hour hand takes 12 hours to make a complete revolution. Multiply that by 2.45 for the equivalent time on the moon.
In get 29.4 hours
Related Questions
physics - A pendulum clock that works perfectly on Earth is taken to the Moon. (...
physics - The acceleration due to gravity on the moon is 1.62 m/s2. What is the ...
physics - The acceleration due to gravity on the moon is 1.62 m/s2. What is the ...
physics - calculate the period and frequency of a 3.500 m long pendulum at the ...
Physics - A pendulum clock is accurate on earth, where the period of its ...
Physics - How do you find the ratio of the new/ old world periods of a pendulum ...
physics - An astronaut on the Moon attaches a small brass ball to a 1.00- m ...
Physics - A. Use the relation 2 m m m GM g R to find the ...
Physics - If a 110kg astronaut weighs 176 Newtons on the moon, what is the ...
physics - Suppose a simple pendulum is used to measure the acceleration due to ...
For Further Reading