a wire whose cross-sectional area is 4mm^2
is stretched by 0.1 mm by a certain load.if a similar wire double the area of cross-section is under the same load,then then elongation would be
ans:
1)0.05mm
Doubling the cross section area decreases the stress by a factor of two. The strain is also reduced by the same factor, so that the elongation is 0.05 mm (instead of 0.1 mm)
Your answer is correct.
Correct
To find the elongation in the wire with double the cross-sectional area, we can use the concept of stress and strain in materials. The strain experienced by a wire is directly proportional to the stress applied to it, and is given by Hooke's Law:
Strain = Stress / Young's Modulus
To compare the elongations, we can assume that the load applied to both wires is the same, and calculate the strain for each wire. Since the load is the same, the stress applied to both wires will be the same.
Now, let's find the value of strain for the wire with the cross-sectional area of 4mm^2. We know that the wire is stretched by 0.1mm. Therefore:
Strain = elongation / original length
Since we are given the elongation (0.1mm), we need to find the original length of the wire. Unfortunately, the original length of the wire is not provided in the question. We could proceed by assuming an arbitrary value for the original length, but this would not allow us to obtain an accurate answer.
Hence, based on the given question, there is not enough information to calculate the elongation for the wire with double the cross-sectional area.