Posted by kalawathi on Monday, February 4, 2013 at 1:46am.
the area of cross section of a wire is 1/100000 m^2 length of the wire is increased by 0.1% a tension of 1000N is produced.the young's modulus of the wire will be?
ans:
1.10^11 N/m^2

Physics  Steve, Monday, February 4, 2013 at 10:37am
E = F/Ao / ∆L/Lo
= 1000/10^5 / 0.001
= 10^3 * 10^5 * 10^3 = 1.0*10^11
If the answer is 1.1*10^11, I'm not sure where I went astray. A change of .1% would be like going from 1000 to 1001, and ∆L/Lo = .001. Maybe I'm misinterpreting the ∆L stuff.
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