Homework Help: Trigonometry

Posted by AwesomeGuy on Monday, February 4, 2013 at 1:30am.

A passenger in an airplane flying at an altitude of 10 kilometers sees two towns directly to the left of the plane. The angles of depression to the towns are 28° and 55°. How far apart are the towns?

Trigonometry - Henry, Wednesday, February 6, 2013 at 6:59pm
tan55o = Y/X1 = = 10km/X1
X1 = 1okm/tan55 = 7 km.

tan28o = Y/(x1+x2) = 10km/(x1+x2).
x1+x2 = 10km/tan28 = 18.8 km.
7+X2 = 18.8
X2 = 11.8 km.

d = 18.8 - 7 = 11.8 km = Distance bet.
the two towns.

Answer this Question

Related Questions

math - A passenger in an airplane flying at an alti- tude of 14 kilometers sees ...
Math - 1) Find the angle of depression from the top of a lighthouse 250 feet ...
Physical Science - an airplane is flying at 600km/h at an altitude of 2.0km. ...
trig - A passenger airplane flying at an altitude of 1.8 km starts its final ...
Calc - A plane that is flying horizontally at an altitude of 6 kilometers and a ...
Physics - The modern Boeing 747 passenger jet airplane cruises at a speed up to ...
physics - An airplane is flying horizontally with a speed of 1000 km/hr (278 m/s...
Trig - I have no idea how to do this problem From an airplane flying 2 ...
physics - Imagine an airplane passenger looking down on two automobiles side by ...
physics - Imagine an airplane passenger looking down on two automobiles side by...

For Further Reading

First Name:
School Subject:
Answer: