Posted by **LaShawn** on Monday, February 4, 2013 at 1:23am.

The sum of the squares of two consecutive positive even integers is one hundred sixty-four. Find the two integers.

- Algebra -
**Steve**, Monday, February 4, 2013 at 5:24am
n^2 + (n+2)^2 = 164

2n^2 + 4n - 160 = 0

n^2 + 2n - 80 = 0

(n+10)(n-8) = 0

...

- Algebra -
**HELP HELP HELP MNHS**, Monday, February 4, 2013 at 5:31am
x 1st + even integer

x+2 2nd + even integer

x^2+(x+2)^2= 164

x^2+x^2+4x+4-164=0

1/2(2x^2+4x-160=0)

x^2+2x-80=0

(x+10)(x-8)=0

x=-10 & x=8, disregard -10 since we are looking for positive integers...

so, x=8 (1st even)

x+2= 10 (2nd even)

## Answer This Question

## Related Questions

- math, algebra - 2a+2ab+2b I need a lot of help in this one. it says find two ...
- algebra - The sum of the squares of two consecutive odd integers decreased by ...
- Algebra - The difference of the cubes of two consecutive odd positive integers ...
- Algebra - The difference of the cubes of two consecutive odd positive integers ...
- algebra! - The difference of the cubes of two consecutive odd positive integers ...
- Algebra - The difference of the cubes of two consecutive odd positive integers ...
- math - The difference of the cubes of two consecutive odd positive integers is ...
- math - The sum of two squares of TWO consecutive even integers is 340. Find the ...
- MATH PLEASE HELP - the sum of the squares pf two postive consecutive even ...
- Algebra - There are three consecutive integers the square of the largest one ...

More Related Questions