Monday

July 28, 2014

July 28, 2014

Posted by **Anonymous** on Sunday, February 3, 2013 at 10:57pm.

- Calculus -
**Reiny**, Sunday, February 3, 2013 at 11:32pmf ' (x) = 2x - 1

so at (0,0) slope = 2(0) -1 = -1

and at (1,0) slope = 2(1) - 1 = +1

since the slopes are negative reciprocals of each other the two tangents are perpendicular.

**Related Questions**

calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...

12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...

Calculus - Could someone please help me with this question; Find the tangent to ...

Calculus - Consider line segments which are tangent to a point on the right ...

calculus - Find an equation of the tangent(s) to the curve at a given point. ...

Calculus - Consider the curve y^2+xy+x^2=15. What is dy/dx? Find the two points ...

calculus - Consider line segments which are tangent to a point on the right half...

calculus!URGENT - Show that the tangent line to the curve y=x^3 at the point x=a...

Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...

Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...