Calculus
posted by Anonymous on .
show that the tangent to the curve f:f(x)= x^2x at the point p1(0,0) is perpendicular to the tangent to the curve at p2(1,0)

f ' (x) = 2x  1
so at (0,0) slope = 2(0) 1 = 1
and at (1,0) slope = 2(1)  1 = +1
since the slopes are negative reciprocals of each other the two tangents are perpendicular.