algebra
posted by lee on .
Could someone check my work;
1. Generate the first five terms in the sequence using the explicit formula.
yn = –5n – 5
–30, –25, –20, –15, –10
30, 25, 20, 15, 10
–10, –15, –20, –25, –30(my answer)
10, 15, 20, 25, 30
2. What is the 15th term in the sequence using the given formula?
cn = 3n – 1
14
57
44
–44(my choice)
3. Write a recursive formula for the sequence 7, 13, 19, 25, 31, ... Then find the next term.
an = an– 1 + 6, where a1 = 7; 37(my choice)
an = an– 1 + 6, where a1 = 37; 7
an = an– 1 – 6, where a1 = 6; –23
an = an– 1 – 6, where a1 = 7; –8
4. Write a recursive formula for the sequence 7, 4, 1, –2, –5, .... Then find the next term.
an = an–1 – 3, where a1 = –8; 7
an = an–1 – 3, where a1 = 7; –8(my answer)
an = an–1 + 3, where a1 = –3; 22
an = an–1 + 3, where a1 = 7; –8
5. Write an explicit formula for the sequence 8, 6, 4, 2, 0, ... Then find a14.
an = –2n + 10; –16
an = –2n + 8; –18
an = –2n + 8; –20
an = –2n + 10; –18
Dont understand this problem.

your first four are correct
#5.
In the explicit formula, you can find any term directly , unlike a recursive, where you have to know the previous term
so if n = 1, we should get 8 from the formula
look at the first and last
the both give you
a(1) = 2(1) = 10 = 8
a(14) = 2(14) + 10 = 28+10= 18
so it has to be the last one. 
Multiple Choice
1. Generate the first five terms in the sequence using the explicit formula.
yn = –5n – 5 (1 point)
(0 pts) –30, –25, –20, –15, –10
(0 pts) 30, 25, 20, 15, 10
(1 pt) –10, –15, –20, –25, –30
(0 pts) 10, 15, 20, 25, 30
1 /1 point
2. What is the 15th term in the sequence using the given formula?
cn = 3n – 1 (1 point)
(0 pts) 14
(0 pts) 57
(1 pt) 44
(0 pts) –44
0 /1 point
3. Write a recursive formula for the sequence 7, 13, 19, 25, 31, ... Then find the next term. (1 point)
(1 pt) an = an– 1 + 6, where a1 = 7; 37
(0 pts) an = an– 1 + 6, where a1 = 37; 7
(0 pts) an = an– 1 – 6, where a1 = 6; –23
(0 pts) an = an– 1 – 6, where a1 = 7; –8
1 /1 point
4. Write a recursive formula for the sequence 7, 4, 1, –2, –5, .... Then find the next term. (1 point)
(0 pts) an = an–1 – 3, where a1 = –8; 7
(1 pt) an = an–1 – 3, where a1 = 7; –8
(0 pts) an = an–1 + 3, where a1 = –3; 22
(0 pts) an = an–1 + 3, where a1 = 7; –8
1 /1 point
5. Write an explicit formula for the sequence 8, 6, 4, 2, 0, ... Then find a14. (1 point)
(0 pts) an = –2n + 10; –16
(0 pts) an = –2n + 8; –18
(0 pts) an = –2n + 8; –20
(1 pt) an = –2n + 10; –18
1 /1 point 
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