Homework Help: chemistry

Posted by Fai on Sunday, February 3, 2013 at 6:10pm.

80ml of hcl is added to 2.5gm of pure cac03 when the reaction is over, then 0.5gm cac03 is left. Find the normality of the acid

The answer 0.5N

Who helps step by step

chemistry - DrBob222, Sunday, February 3, 2013 at 6:20pm
mL x N x m.e.w. = grams.
80 x N x 0.050 = 2.0

grams CaCO3. Started with 2.5, finished with 0.5, used 2.0 g
m.e.w. CaCO3 = 100/2000 = 0.050

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