Posted by **Julia** on Sunday, February 3, 2013 at 12:41pm.

A projectile is fired at 45.0° above the horizontal. Its initial speed is equal to 42.5 m/s. Assume that the free-fall acceleration is constant throughout and that the effects of the air can be ignored. What is the maximum height reached by the projectile?

At what time after being fired does the projectile reach this maximum height?

- Physics please help!! -
**Damon**, Sunday, February 3, 2013 at 1:23pm
Vi = 42.5 sin 45 = 30 m/s

v = Vi - 9.81 t

0 = 30 - 9.81 t

t = 3.06 seconds to top

h = 0 + Vi t - (1/2)9.81 t^2

h = 30(3.06) - 4.9 (3.06)^2

= 91.8 - 45.9

= 91.7 m

- Physics -
**chikodi john**, Friday, May 29, 2015 at 11:49am
a ball thrown vertically upward from the top of a tower 60m high a velocity of 30ms what is the maximum height above the ground level.how long does it take to reach the ground

## Answer This Question

## Related Questions

- Physics - A projectile is fired at 65.0° above the horizontal. Its initial speed...
- Physics - A projectile is fired at 32.5° above the horizontal. Its initial speed...
- physics - A projectile is fired at 30.0° above the horizontal. Its initial speed...
- physics - A projectile was fired at 35 degrees above the horizontal. At the ...
- physics - A projectile is fired into the air from the top of a cliff of height h...
- physics - A projectile is fired into the air from the top of a cliff of height h...
- Physics - A projectile is fired into the air from the top of a cliff of height h...
- physics - A projectile is fired into the air from the top of a cliff of height h...
- physics - A projectile is fired at 33.1° above the horizontal. Any effects due ...
- Physics - A cannonball is fired with initial speed v0 at an angle 30° above the ...

More Related Questions