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January 26, 2015

January 26, 2015

Posted by **Julia** on Sunday, February 3, 2013 at 12:41pm.

At what time after being fired does the projectile reach this maximum height?

- Physics please help!! -
**Damon**, Sunday, February 3, 2013 at 1:23pmVi = 42.5 sin 45 = 30 m/s

v = Vi - 9.81 t

0 = 30 - 9.81 t

t = 3.06 seconds to top

h = 0 + Vi t - (1/2)9.81 t^2

h = 30(3.06) - 4.9 (3.06)^2

= 91.8 - 45.9

= 91.7 m

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