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March 1, 2015

March 1, 2015

Posted by **Vanessa** on Sunday, February 3, 2013 at 12:33pm.

h=0.0008d^2-0.384d were h metres represents the height and d metres represents the horizontal distance.

a) What is the vertical distance from the top of a support tower to the lowest point on a cable, to the nearest metre?

b)What is the length of the main span?

c) At a horizontal distance of 50m from one end of the cable, how far is the cable below the top of the support towers, to the nearest metre?

- Grade 10 Math -
**Steve**, Sunday, February 3, 2013 at 2:21pmh = .0008(d^2-480d)

= .0008(d^2-480d+240^2 - 240^2)

= .0008(d-240)^2 - 46.08

So, the vertex is at (240,-46.08)

That means the drop is 46 m

h = .0008d(d-480)

h=0 at d=0,480

The main span is 480 m

h(50) = .0008*50(-430) = -17.2

The point is 17 m below the top

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