Posted by bryan on Sunday, February 3, 2013 at 12:28pm.
If the rope is of length h, and the boat is x away from the dock,
h^2 = 1+x^2
When x=8, h = √65
2h dh/dt = 3x dx/dt
Since dh/dt = -1,
2√65 (-1) = 3*8 dx/dt
dx/dt = -√65/12
Since dx/dt < 0, the boat is approaching the dock at about 0.67 m/s
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