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April 25, 2014

April 25, 2014

Posted by **michael** on Sunday, February 3, 2013 at 1:59am.

station with a constant acceleration. At the end of 5.59 s, it is moving at 11.5154 m/s.

What is the train’s displacement in the first 4.15337 s of motion?

Answer in units of m

- Physics -
**drwls**, Sunday, February 3, 2013 at 7:56amThe acceleration rate is

a = 11.5154/5.59 = 2.06 m/s^2

Displacement at t = 4.15337s =

(1/2) a t^2 = 17.77 m

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